(4/5)^2x+4=(25/16)^3x+6

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Solution for (4/5)^2x+4=(25/16)^3x+6 equation: 



(4/5)^2x+4=(25/16)^3x+6

We move all terms to the left:

(4/5)^2x+4-((25/16)^3x+6)=0



Domain of the equation: 5)^2x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 16)^3x+6)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+4/5)^2x-((+25/16)^3x+6)+4=0

We calculate fractions


64^3x/5^2x*16)^3x+6))+(-125^2x/5^2x*16)^3x+6))+4=0

We can not solve this equation

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